Let and be groups. Prove that is abelian if and only if and are abelian.
Suppose and . Then . Since two pairs are equal precisely when their corresponding entries are equal, we have and . Hence and are abelian.
Suppose . Then we have . Hence is abelian.
Suppose and . Then . Since two pairs are equal precisely when their corresponding entries are equal, we have and . Hence and are abelian.
Suppose . Then we have . Hence is abelian.
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