Let
be a group, and let
be an element of finite order; say
. Use the Division Algorithm to show that any integral power of
is equal to one of the elements in the set
. Conclude that
is precisely the set of distinct elements of the cyclic subgroup of
generated by
.
Let
. By the Division Algorithm, there exist unique integers
such that
and
. Thus
, where
.
Hence the cyclic subgroup of
generated by
is
; moreover, by a previous result, the elements of
are all distinct.
Let
Hence the cyclic subgroup of
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